1.#第一题 i1 sum0 for i in range(1,101): sumsum 1/i print(sum)运行截图2.#第二题 nint(input(请输入n值: )) i1 sum0 for i in range(1,n1): if (i%2!0): sumsum 1/i else: sumsum - 1/i print(sum)运行截图3#第三题 nint(input(请输入n值: )) sum0 total0 hh0 for i in range(1,n1): hhitotal sumsum 1/hh total total i print(sum)运行截图4#第四题 a2 sum10 total0 nint(input(请输入前:)) for i in range(1,n1): sum1sum110**(i-1)*2 totaltotalsum1 print(total)运行截图5#第五题 sum1 total1 hh0 i 1 while True: hhi*total total total *i term 1/hh if (term1e-6): break sum sum 1 /hh i i 1 print(sum)运行截图6#第六题 sum1 for i in range(1,100000000): itwo2*i1 if (i%2!0): sumsum - 1/itwo else: sumsum 1/itwo sum24*sum print(sum2)运行截图
1.#第一题 i1 sum0 for i in range(1,101): sumsum 1/i print(sum)运行截图2.#第二题 nint(input(请输入n值: )) i1 sum0 for i in range(1,n1): if (i%2!0): sumsum 1/i else: sumsum - 1/i print(sum)运行截图3#第三题 nint(input(请输入n值: )) sum0 total0 hh0 for i in range(1,n1): hhitotal sumsum 1/hh total total i print(sum)运行截图4#第四题 a2 sum10 total0 nint(input(请输入前:)) for i in range(1,n1): sum1sum110**(i-1)*2 totaltotalsum1 print(total)运行截图5#第五题 sum1 total1 hh0 i 1 while True: hhi*total total total *i term 1/hh if (term1e-6): break sum sum 1 /hh i i 1 print(sum)运行截图6#第六题 sum1 for i in range(1,100000000): itwo2*i1 if (i%2!0): sumsum - 1/itwo else: sumsum 1/itwo sum24*sum print(sum2)运行截图
