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B3619 10 进制转 x 进制 - 洛谷

#include <bits/stdc++.h>using namespace std;
#define fs first
#define sc second
#define endl '\n'
#define all(x) x.begin(), x.end()
typedef long long ll;
typedef pair<int, int> PII;char a[40];void solve(){int n,x;cin>>n>>x;int h=0;while(n>=x){int t=n%x;if(t>=10) a[h++]='A'+t-10;else a[h++]=t+'0';n/=x;}if(n>=10) a[h++]='A'+n-10;else a[h++]=n+'0';for(int i=h-1;i>=0;i--)cout<<a[i];
}int main(){cin.tie(0);cout.tie(0);ios::sync_with_stdio(0);int t;t=1;while (t--){solve();}return 0;
}